What is the limit as x approaches -1

Question

of

x - 5
---------------------
4x(squared)-6x+ 3

Answer 1

The first step in any single function limit question such as this is to substitute the "approach value" into the function.
If you get a real number answer, that is it, you are done.

so here limit (x-5)/(4x^2 - 6x + 3) as x ---> -1
= -6/(4+6+3)
= -6/13

the nasty ones is when you get 0/0
In that case you are guaranteed that the expression will factor.