Asked by Erica
What is the limit as x approaches infinity of 4xsin(1/x)?
Can you also show me how you get the answer?
Thank you so much!!
Can you also show me how you get the answer?
Thank you so much!!
Answers
Answered by
Anonymous
lim (x --> inf) 4x * sin(1/x)
Let t = 1/x as x --> inf, t --> 0
lim (t --> 0) 4 (1/t) * sin(t)
lim (t --> 0) 4 * sin(t)/t
lim (t--> 0) 4 * lim (t --> 0) sin(t) / t
= 4 * 1
= 4
I find that on Internet. Sometimes when you want math help,just retype your question in google.Many times you will find answer.
Let t = 1/x as x --> inf, t --> 0
lim (t --> 0) 4 (1/t) * sin(t)
lim (t --> 0) 4 * sin(t)/t
lim (t--> 0) 4 * lim (t --> 0) sin(t) / t
= 4 * 1
= 4
I find that on Internet. Sometimes when you want math help,just retype your question in google.Many times you will find answer.
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