Asked by anonymous
A sequence of polynomials gk(x) is defined recursively as follows.
g0(x)=x; gk+1(x)=gk(x^2+2x)−gk(x)
Find the last three digits of the coefficient of x^2 in g299(x).
g0(x)=x; gk+1(x)=gk(x^2+2x)−gk(x)
Find the last three digits of the coefficient of x^2 in g299(x).
Answers
Answered by
Alestair
941
Answered by
anonymous
sorry, but wrong answer...
repeating the question again ->
A sequence of polynomials gk(x) is defined recursively as follows:
g0(x)=x
gk+1(x)=gk(x^2+2x)−gk(x)
Find the last three digits of the coefficient of x^2 in g299(x).
repeating the question again ->
A sequence of polynomials gk(x) is defined recursively as follows:
g0(x)=x
gk+1(x)=gk(x^2+2x)−gk(x)
Find the last three digits of the coefficient of x^2 in g299(x).
Answered by
Danny
634
Answered by
debjit
That's wrong. I thint, that should be 925.
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