Asked by kabhir
the polynomials P(x)= kx^3+3x^2-3 and Q(x)= 2x^3-5x+k when divided by (x-4) leave the same remainder the value of k is
Answers
Answered by
Reiny
p(4) = 64k + 48 - 3
= 64k + 45
Q(4) = 128 - 20 + k
= k + 108
by the remainder theorem , each of these are the remainders when divided by x-4
But they are equal ...
64k + 45 = k + 108
63k = 63
k = 1
= 64k + 45
Q(4) = 128 - 20 + k
= k + 108
by the remainder theorem , each of these are the remainders when divided by x-4
But they are equal ...
64k + 45 = k + 108
63k = 63
k = 1
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