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debjit

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ABCD is a square. P is a point inside the square, such that AP:BP:CP=1:2:3. What is the value (in degree) of angle APB?
1. 9 answers
2. 2,805 views

Yeah...got it. And I have also find a solution, without co-ordinate geometry...if we take the point 'B' at the bottom right side of the figer, and the point 'A' in the bottom left side, then, rotate the triangle BPC 90 degrees in left side, with respect to
Mathmate, it seems that, you took DP=3, but according to my question CP=3. So, you have drawn BD, but it should be CD. Though I can not understand the process of iteration or Newton's method to solve that two equations. Can you please clear that part?
Steve, how did you solve that three equations? And according to your solution, where is the origine?
Plz give the full worked solution.I have failed to find the answer.
Plz give the full worked solution. I have failed find the answer.
no, it is wrong
is the answer 25?
is the answer 53?
no, its wrong
That's wrong. I thint, that should be 925.
No no....that should be 792
Is the answer 920? i.e. (8+120+792)
Is the ans (4 64 324)=392 ? I don't think, that these three values are the only values of 'n'. Because, the question is to find the last three digits of the sum. But here, the sum itself is a three digit number, so, I think, there must be some other values
how? what will be when the distance is 5 m and, coefficient of kinetic friction equal to 0.1?
how?

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