Asked by Talbert

A model rocket is launched vertically upward so that its height (measured in feet) t sec after launch is given by the following.
h(t) = -16t2 + 272t + 8

(a) Find the times when the rocket is at a height of 488 ft.
t = sec (smaller value)
t = sec (larger value)

(b) How long is the rocket in flight? (Round your answer to the nearest whole number.)

Answers

Answered by Steve
(a) just solve
-16t^2 + 272t + 8 = 488

(b) solve when h(t) = 0
Answered by cris
48
Answered by jon
its 44

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