Asked by nicole
A model rocket is launched from a height of 50 feet. the formula: h=-16t^2+70t+50 describes the rocket's height,h,in feet t seconds after it was launched. how long will it take the rocket to reach the ground.
Answers
Answered by
Reiny
when it hits the ground, h = 0
-16t^2 + 70t + 50 = 0
8t^2 - 35t - 25 = 0
(t-5)(8t + 5) = 0
t = 5 or t = -5/8, but t can't be negative
so it will hit the ground in 5 seconds.
-16t^2 + 70t + 50 = 0
8t^2 - 35t - 25 = 0
(t-5)(8t + 5) = 0
t = 5 or t = -5/8, but t can't be negative
so it will hit the ground in 5 seconds.
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