Asked by Cassie
A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation
y = –0.04x2 + 8.3x + 4.3 , where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land? Round your answer to the nearest hundredth meter.
208.02 m
416.03 m
0.52 m
208.19 m
I think it is A...?
y = –0.04x2 + 8.3x + 4.3 , where x is the horizontal distance, in meters, from the starting point on the roof and y is the height, in meters, of the rocket above the ground. How far horizontally from its starting point will the rocket land? Round your answer to the nearest hundredth meter.
208.02 m
416.03 m
0.52 m
208.19 m
I think it is A...?
Answers
Answered by
Reiny
I am sure you meant
y = -.04x^2 + 8.3x+ 4.3
when it lands, y = 0
.04x^2 - 8.3x - 4.3=0
x = (8.3 ± √69.578)/.08
= 208.0167.. or a negative value of x
= 208.02 m
y = -.04x^2 + 8.3x+ 4.3
when it lands, y = 0
.04x^2 - 8.3x - 4.3=0
x = (8.3 ± √69.578)/.08
= 208.0167.. or a negative value of x
= 208.02 m
Answered by
Cassie
Thank you...
Answered by
i just got 100
wow old question
Answered by
LlammaLove
Yea so old.
Answered by
Sugondeez
Ur mom
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.