Asked by Derrick
A model rocket is launched at an angle of 80 degrees aboce the x axis, with a velocity of 30m/s. How high will the rocket be 5 seconds after launch?
ROund your answer to the nearest tenth
ROund your answer to the nearest tenth
Answers
Answered by
Henry
Vo = 30m/s[80o]
Yo = 30*sin80 = 29.54 m/s.
hmax = (V^2-Vo^2)/2g
hmax = (0-29.54^2)/-19.6 = 44.52 m
Tr = -Vo/g = -29.54/-9.8 = 3.0 s = Rise time,
Tf = 5-3 = 2 s. = Fall time.
h = ho - 0.5g*t^2
h=44.52 - 4.9*2^2 = 24.92 m. after 5 s.
4.9*2^2 = 19.6
Yo = 30*sin80 = 29.54 m/s.
hmax = (V^2-Vo^2)/2g
hmax = (0-29.54^2)/-19.6 = 44.52 m
Tr = -Vo/g = -29.54/-9.8 = 3.0 s = Rise time,
Tf = 5-3 = 2 s. = Fall time.
h = ho - 0.5g*t^2
h=44.52 - 4.9*2^2 = 24.92 m. after 5 s.
4.9*2^2 = 19.6
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