Asked by Robin
Find the equation of the tangent line to the curve y=2tan(x) at the point (pi/4,2).
Answers
Answered by
Steve
y'(x) = 2sec^2(x)
y'(pi/4) = 2(2) = 4
So, now you have a point and a slope, so the line is ?
y'(pi/4) = 2(2) = 4
So, now you have a point and a slope, so the line is ?
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