Asked by Jnr John

If a varies jointly as b and the square root of c, and a = 21 when b = 5 and c = 36, find a when b = 9 and c = 225.
Answered by kuai

a = kbsqrt(c)

21 = k5sqrt936)

21 = 30k

k = 21/30

a = (21/30)*b sqrt(c)

a = (21/30) *9 8sqrt(2250

a = 189/2

Answered by kuai
1 = k5sqrt(36)

21 = 30k

k = 21/30

a = (21/30)*b sqrt(c)

a = (21/30) *9 sqrt(225)

a = 189/2
There are no AI answers yet. The ability to request AI answers is coming soon!