Asked by Joe
y varies jointly as X and Z. y=64 when x=4 and z=8. Find y when x=8 and z=6
Answers
Answered by
Bosnian
y = k ∙ x ∙ z
When x = 4 , y = 64 and z = 8:
y = k ∙ x ∙ z
64 = k ∙ 4 ∙ 8
64 = 32 k
Divide both sides by 32
64 / 32 = k
2 = k
k = 2
When x = 8 and z = 6:
y = k ∙ x ∙ z
y = 2 ∙ x ∙ z
y = 2 ∙ 8 ∙ 6
y = 2 ∙ 48
y = 96
When x = 4 , y = 64 and z = 8:
y = k ∙ x ∙ z
64 = k ∙ 4 ∙ 8
64 = 32 k
Divide both sides by 32
64 / 32 = k
2 = k
k = 2
When x = 8 and z = 6:
y = k ∙ x ∙ z
y = 2 ∙ x ∙ z
y = 2 ∙ 8 ∙ 6
y = 2 ∙ 48
y = 96
Answered by
Steve
y = kxz
so, y/(xz) = k, a constant
You want y such that
y/(8*6) = 64/(4*8)
y/48 = 2
y = 96
so, y/(xz) = k, a constant
You want y such that
y/(8*6) = 64/(4*8)
y/48 = 2
y = 96
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