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kuai
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y = mx + b y - 2x = 4 y - 2x +2x = 2x + 4 y = 2x + 4 slope is 2
1/x^4
-16(t^2-4t-12) =0 (t-6)(t+2) =0 t - 6 = 0 t = 6
x^2 -25 =0 (x -5)(x+5) =0
y = 0 0= .25x + 15 -15 = .25x x = -60 x =0 y= .25(0) + 15 y = 15 Slope is .25 (-60,0),(0,15)
mean = 9.3, median = 10, mode = 13
A = LW L = w-1 120 =(w-1)w 120 = w^2-w w^2-w-120 =0
P=2l+2w 70 = 2(17) + 2w 70 = 34 +2w 70-34 = 34-34 +2w 36 = 2w w = 18
y = mx + b f(x) = 2m + b = 1 f(x) = 4m + b = 0 f(x) = 6m + b = -1 -1(2m + b = 1) 4m + b = 0 -2m -b = -1 4m + b = 0 2m = -1 m = -1/2 2(-1/2) + b = 1 -1 + b = 1 -1+ 1 + b = 1 + 1 b = 2 y = mx +b y = -1/2x + 2
x = 7-(1/8)y x-7 = -1/8y -8x+56 =y
6/30 = 10/x 300 = 6x x = 50 50/30 =x/10
1) 5h ¨C 9 = ¨C16 + 6h -9+16 = 6h-5h 7 = h 4x + 4 = 9x ¨C 36 36 +4 = 9x-4x 40 = 5x 8 =x 5) k < 0 6) q ¡Ý ¨C1 7) p < 8 8)g > 90 9)n ¨C 6 ¡Ý 2; n ¡Ý 8
1/6 ln(x^2-2)+c
p(x) =-4x^2+48x-18 P'(x)= -8x +48 0 = -8x +48 8x =48 x = 6 5)C(x) = 20x+600 C(31)-C(30) = 20(31)+600-([20(30)+600]) 1220- 1200= 20 C(x) 20x +600 C'(x) = 20
$275 + 80n = $835 275-275 +80n = 835-275 80n = 560 80n/80 = 560/80 n = 7
YES. IF YOUR PROFESSOR SAID THAT YOUR ANSWER SHOULD BE IN PERCENT. P = 142/507 = 0.28 SD = SQRT( .28*.72/507) SQRT(0.2016/507) = 0.0199 1-a = .95 a =0.05 za/2 = z0.025 = 1.96 Z = 1.96 p -+ za/2 * SD/sqrt(n) 0.28-+1.96*0.0199 0.28-+ 0.039 ( 0.241, 0.319) IF
YES. IF YOUR PROFESSOR SAID THAT YOUR ANSWER SHOULD BE IN PERCENT. P = 142/507 = 0.28 SD = SQRT( .28*.72/507) SQRT(0.2016/507) = 0.0199 Z = 1.96 0.28-+1.96*0.0199 0.28-+ 0.039 ( 0.241, 0.319)
the rest are ok y= mx +b -4 = (-15)(1/2) +b -4 = -15/2 + b -4+15/2 = b 7/2 = b y = mx +b y = x/2 +7/2 Ax + By = C 2(y) = 2(x/2 + 7/2) 2y = x + 7 -x +2y = 7
g/4 +7 = 10 g/4 = 10-7 g/4 = 3 4(g/4) =3(4) g = 12
1. 8^2 x^2(x+6)^2 = 2. 480 = (w+10)w
99% confidence interval z = 2.575 p hat = 68/87 =0.7816 E= Za/2 *sqrt((phat(1-phat)/n)) E = 2.575*sqrt(0.7816*0.2184/87) E = 0.1141 phat-E < P < Phat+ E 0.7816-0.1141
A = P( 1+ r/n)^nt A= 200(1+.08/2)^2(10) = ?
1650-1200 = 450 1200*0.08 = 96 450/96 = 4.7 years
-6x + 24y =-60 6x - 24y = 60 there are infinite solution.
92/9+10/3 (92+30)/9 = 122/9 13 5/9
Ax +By = C y-8 = 2x +6 y-8-6 =2x + 6 -6 y-14 = 2x y-y -14 = 2x -y -14 = 2x-y C
a. mean = (1+3+5+3+2+29+3+4+2+1+2)/11 =55/11= 5 (1-5) = x (x-x̅) (x-x̅)^2 1 -4 16 3 -2 4 5 0 0 3 -2 4 2 -3 9 29 24 576 3 -2 4 4 -1 1 2 -3 9 1 -4 16 2 -3 9 b. Range= highest value - lowest value Range =29-1 = 28 c. variance = (x-x̅)^2 = 648 648/(11-) =
1. x^2 = 22^2+ 27^2 -2(22)(27)cos60 x^2 =1213 -1188cos60 x^2 =619 x= 24.9 miles
you use that formula when you know what to do. nCr nPr
The critical region is 0.632. larger value fail to reject the null hypothesis. there is no enough evidence to support that the claim.
3p+1 = 5p-15 3P+ 1+15 = 5P -15 +15 3p +16 = 5p 3p-3p+16 = 5p -3p 16 = 2p p = 8
p = 0.68 n = 800 µ = np µ = 800(.68) = 544 Standard deviation = √(np(1-p) ) = √(800(.68)(.32) ) = 13.1939 µ±2σ (544 -2(13.193), 544+2(13.1939)) (517.6, 570.4) 554 is not unusual because it is in interval.
P = y^2 Q = xy �ç[0,9]�ç[0(�ãx)](�ÝQ/�Ýx-�Ýp/�Ýy)dy dx �ç[0, 9]�ç[0, �ãx ](y-2y)dy dx �ç[0,9]�ç[0, �ãx](-y)dy dx �ç[0,9]-x/2 dx =(-x^2)/4 [0, 9] = (-81)/4
w = kav 225 = k(25)(40) 225 = 1000k k = 9/40 w = 9/40 av 270 = 9/40(40)(v) 270 = 9v 270/9 = v v = 30 mile per hour
v = kha 92 = k(12)(23) 92 = 276k k = 92/276 = 1/3 v = 1/3ha v = (1/3)(17)(27) v = 153
1 = k5sqrt(36) 21 = 30k k = 21/30 a = (21/30)*b sqrt(c) a = (21/30) *9 sqrt(225) a = 189/2
a = kbsqrt(c) 21 = k5sqrt936) 21 = 30k k = 21/30 a = (21/30)*b sqrt(c) a = (21/30) *9 8sqrt(2250 a = 189/2
y = kxz 33 =k *9* 12 33 = 108k k = 33/108 y = (33/108)(16)(22) y = 242/3
this is b answer. x^3 + 3x + 2 remainder 2
x^3 + x^2 + 3x - 12 remainder 16
12x-9y +2 =0 -12x-2 = -9y -12x/-9 -2/-9 = -9y/-9 y = 4x/3+2/9 The slope is 4/3 and y-intercept is (0, 2/9)
(x-7)^2 (x-7)(x-7) = x^2-7x-7x+49 = x^2 - 14x + 49
L = 4x-7 w = 3x+6 A = L*w A = (4x-7)(3x+6) = 12x^2+24x+-21x+-42 A = 12x^2+3x-42
