Question
Find all first partial derivatives:
f(x,y)=e^(xy)cosx
f(x,y)=e^(xy)cosx
Answers
Steve
Fx = ye^(xy)cosx - e^(xy)sinx
= e^(xy) (ycosx - sinx)
Fy = xe^(xy) cosx
= e^(xy) (ycosx - sinx)
Fy = xe^(xy) cosx
Andy
Find, f1(0,180°) if (x,y)= e^(xy)cos(x+y).
Andy
Find, f1(0,180°) if f(x,y)=e^(xy)cos(x+y)