Ask a New Question

Asked by John

How would you find the derivative of this implicit function?

1+x=sin(xy^2)
14 years ago

Answers

Answered by Yu
Use Chain Rule
1=cos(xy^2)(y^2+2xyy')
1=cos(xy^2)y^2+(2xy)cos(xy^2)(y')
[1-cos(xy^2)y^2]/[(2xy)cos(xy^2)]=y'
14 years ago
There are no AI answers yet. The ability to request AI answers is coming soon!

Submit Your Answer


We prioritize human answers over AI answers.

If you are human, and you can answer this question, please submit your answer.

Related Questions

how would you find the derivative of: f(x) = (x^2 + 1)^ (2-3x) Help my find the first derivative of these two questions, please. y = 6-e^x (Ans at the back of t... How would you find the derivative of (3/(x^3-4)) by using the chain rule? y = e^2xsin3x Find the derivative. So I used the product rule and I got sin3x(e^2x)+cos^3x(e^2x). B... How would you find the derivative of f(x)=1/sqrtx using limits? I know how to do problems with a fr... ex: Find the indicated derivative using implicit differentiation. e^x/y^2= 8 + e^y; dy/dx Plea... s(x)=log3(x^2+6x) find derivative? find d^2y/dx^2 (second derivative) for y=cos^2 4x how to find the second derivative of quotient rule? f(x): 700v^2 + 3450/v f'(x) : 700v^2 -3450/v^2... Find all first partial derivatives: f(x,y)=e^(xy)cosx
Submit Your Answer

Question

How would you find the derivative of this implicit function?

1+x=sin(xy^2)

Ask a New Question
Archives Contact Us Privacy Policy Terms of Use