Asked by Joe
How would you find the derivative of (3/(x^3-4)) by using the chain rule?
Answers
Answered by
drwls
Let u(v) = 3/v and v(x) = x^3 -4
The original function is u[v(x)]
du[v(x)]/dx = du/dv * dv/dx
= -3/v^2 * (3x^2)
= -x^2/(x^3 -4)^2
The original function is u[v(x)]
du[v(x)]/dx = du/dv * dv/dx
= -3/v^2 * (3x^2)
= -x^2/(x^3 -4)^2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.