assuming you meant
f(x,y)=2x^3y^2+y^3
fx = 6x^2y^2
fy = 4x^3y+3y^2
Find the first partial derivative of the functon
f
(
x
,
y
)
=
2
x
3
y
2
+
y
3
1 answer
f
(
x
,
y
)
=
2
x
3
y
2
+
y
3
1 answer
1 answer
2 answers
3 answers
1 answer