Asked by Olajumoke
Find the first partial derivative of the functon
f
(
x
,
y
)
=
2
x
3
y
2
+
y
3
f
(
x
,
y
)
=
2
x
3
y
2
+
y
3
Answers
Answered by
Steve
assuming you meant
f(x,y)=2x^3y^2+y^3
f<sub><sub>x</sub></sub> = 6x^2y^2
f<sub><sub>y</sub></sub> = 4x^3y+3y^2
f(x,y)=2x^3y^2+y^3
f<sub><sub>x</sub></sub> = 6x^2y^2
f<sub><sub>y</sub></sub> = 4x^3y+3y^2
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