a person jumps off of a 6 foot high diving board with an initial velocity of 13 feet per second. how many seconds does it take the person to hit the water?

Answer 1

the equation would be
h = -16t^2 + 13t + 6 , where h is the height above the water in ft, and t is in seconds

so we want h=0
0 = -16t^2 + 13t +6
16t^2 - 13t - 6 = 0
t = (13 ± √553)/32
= appr 1.14 or a negative, which we must reject

it would take about 1.14 seconds