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a person jumps off of a 6 foot high diving board with an initial velocity of 13 feet per second. how many seconds does it take the person to hit the water?
12 years ago

Answers

Reiny
the equation would be
h = -16t^2 + 13t + 6 , where h is the height above the water in ft, and t is in seconds

so we want h=0
0 = -16t^2 + 13t +6
16t^2 - 13t - 6 = 0
t = (13 ± √553)/32
= appr 1.14 or a negative, which we must reject

it would take about 1.14 seconds
12 years ago

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