Asked by amy
a person jumps off of a 6 foot high diving board with an initial velocity of 13 feet per second. how many seconds does it take the person to hit the water?
Answers
Answered by
Reiny
the equation would be
h = -16t^2 + 13t + 6 , where h is the height above the water in ft, and t is in seconds
so we want h=0
0 = -16t^2 + 13t +6
16t^2 - 13t - 6 = 0
t = (13 ± √553)/32
= appr 1.14 or a negative, which we must reject
it would take about 1.14 seconds
h = -16t^2 + 13t + 6 , where h is the height above the water in ft, and t is in seconds
so we want h=0
0 = -16t^2 + 13t +6
16t^2 - 13t - 6 = 0
t = (13 ± √553)/32
= appr 1.14 or a negative, which we must reject
it would take about 1.14 seconds
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