Question

A person jumps from the roof of a house 3.0 m high. When he strikes the ground below, he bends his knees so that his torso decelerates over an approximate distance of 0.60 m. The mass of his torso (excluding legs) is 48 kg.

*How do I find the average force exerted on his legs by his torso during deceleration?

Answer 1

force*distance=mgh
workdoneinabsorbind enery=energyfromfall

solve for force.

Answer 2

but i solved for the force and it did not come out as the right anser i did Fd=mgh then said F(.6)=(48)(9.8)(3) but its wrong???

Answer 3

I don't know. Do you think it means on each leg individually?

Answer 4

hi can u help me in my home work

Answer 5

state the law of conservation of linear momentum and describe its consequences.