Question
A person jumps from the roof of a house 3.0 m high. When he strikes the ground below, he bends his knees so that his torso decelerates over an approximate distance of 0.60 m. The mass of his torso (excluding legs) is 48 kg.
*How do I find the average force exerted on his legs by his torso during deceleration?
*How do I find the average force exerted on his legs by his torso during deceleration?
Answers
bobpursley
force*distance=mgh
workdoneinabsorbind enery=energyfromfall
solve for force.
workdoneinabsorbind enery=energyfromfall
solve for force.
Corey
but i solved for the force and it did not come out as the right anser i did Fd=mgh then said F(.6)=(48)(9.8)(3) but its wrong???
bobpursley
I don't know. Do you think it means on each leg individually?
lolo
hi can u help me in my home work
Anonymous
state the law of conservation of linear momentum and describe its consequences.