A. Fg = (Vs+Vg)/(Vs-Vp) * Fp.
578 = (343+0)/(343-Vp) * 475.
578 = 343/(343-Vp) * 475,
Divide both sides by 475:
1.21 = 343/(343-Vp),
416-1.21Vp = 343, Vp = 60.3 m/s.
B. Fg = (Vs-Vg)/(Vs+Vp) * Fp.
Fg = (343-0)/(343+60.3) * 475.
Since the distance between the people on the gnd. and the person is now increasing, the freq. heard(Fg) is less than 475
Hz.
A person jumps out of a helicopter in mid-air to retrieve a small metal ball. He screams at 475Hz, but people on the ground hear him scream at 578Hz.
The person is falling at __(m/s)
Once he grabs the metal ball, he is pulled back up to the helicopter at the same speed as he was falling.
People on the ground now hear him scream at __(Hz)
Take the speed of sound to be 343m/s.
1 answer