A person jumps from a window 57 meters high and is caught in a firefighter's net which stretches 0.6 meter. To the nearest tenth of a m/s^2, what is the magnitude of the person's acceleration in the net?

2 answers

mgh=f*d=mad
solve for a
Bobpursley, if you could, would be able to elaborate on what you mean by "mgh=f*d=mad"

I am new to physics and I have pretty much this same exact problem for my homework and I can't figure it out on my own. I have searched the book and nothing that is in the book that has been covered thus far seems to click as for how I can solve this problem.