Asked by anonymous

solve for each of the variables.
a. 8-(7x+3)/4-2(3-x)=0
c. [3(x+3)]/5+y/2+2z=-1
x/3+[(5y-2)/4]+z=0
x-[2(y+1)/3]-3z=-2
d. 1/(x+3)-2/(x-2)=5/(x+3)
Answered by Henry
Multiply both sides by 4:
a. 32--7x-3 -24+8x = 0
x + 32-27 = 0
X = -5.