Asked by Anonymous
solve for each of the variables:
3(x+3)/5+y/2/=2z=-1
x/3+5y-2/4+z=0
z-2(y+1)/3-3z=-2
3(x+3)/5+y/2/=2z=-1
x/3+5y-2/4+z=0
z-2(y+1)/3-3z=-2
Answers
Answered by
Steve
Adding in some spacing for readability, and assuming the usual typos, we have
3(x+3)/5 + y/2 + 2z = -1
x/3 + 5y - 2/4 + z=0
z - 2(y+1)/3 - 3z = -2
(x,y,z) = 1/514 (-3477,230,266)
An awkward set of solutions, so I assume that my auto-correcting skills are off. Maybe you could clarify, and hey, what the heck, show some work of your own...
3(x+3)/5 + y/2 + 2z = -1
x/3 + 5y - 2/4 + z=0
z - 2(y+1)/3 - 3z = -2
(x,y,z) = 1/514 (-3477,230,266)
An awkward set of solutions, so I assume that my auto-correcting skills are off. Maybe you could clarify, and hey, what the heck, show some work of your own...
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