Asked by Anon

Find an equation for the line with y-intercept 3 that is perpendicular to the line 3y=2x-4.
A. 2y=6-3x
B. 2y=3x+6
C. 3y=9-2x
D. 3y=2x+9
Answered by Henry
y = -3x/2 + 3
Multiply both sides by -2:
-2y = 3x - 6
2y = -3x + 6
2y = 6 - 3x

Answer = A.
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