Asked by Bethany
I need to find the symmetry of a polynomial function graph. Is this correct?
f(x)=x^2+2x-1
x=-6/2x=-2/2*1
x=-2/2=-1
It is symmetric about x=-1/-2
f(x)=x^2+2x-1
x=-6/2x=-2/2*1
x=-2/2=-1
It is symmetric about x=-1/-2
Answers
Answered by
Anonymous
So I'm a bit confused to what you have done >.<.. To find the symmetry for a trinomial it is 2ax + b = 0. So you'll have to use this equation and solve for x. If you haven't learned this equation yet, a is the coefficient of x^2 and b is the coefficient of x.
Answered by
Anonymous
Oh NVM, I see what you did now >.<. You were correct up to x=-2/2=-1. However, your answer is x = -1/-2(which is 1/2)? How did x go from -1 to 1/2 xD?
Answered by
Bethany
My answer is suppose to be x= -1/2. Is that correct?
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