Asked by jacob
find the axis of symmetry f(x)=-2x2-12x+8find the axis of symmetry f(x)=-2x2-12x+8
Answers
Answered by
Mgraph
f(x)=2(x^2-6x+4)=2(x^2-6x+9-5)=
=2((x-3)^2-5)=2(x-3)^2-10
The vertical axis x=3
=2((x-3)^2-5)=2(x-3)^2-10
The vertical axis x=3
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