Question

p varies jointly as u and B^2 when u = 4 and B = 5, P = 300. find P when u is 1 and Bis 11

Answer 1

p = kub^2
300 = k(4)(25)
k = 3

so, now we know k=3, and thus

p(u,v) = 3ub^2
p(1,11) = 3(1)(121) = 363