Asked by Tima
Find the equation of the line tangent to
f(x) = xe^-x
at the point where x = 0. What does this tell you about the behavior of the graph when x = 0?
f(x) = xe^-x
at the point where x = 0. What does this tell you about the behavior of the graph when x = 0?
Answers
Answered by
Reiny
first of all , when x = 0 , f(0) = 0
so the point is (0,0)
f'(x) = x(-e^-x) + e^-x
when x = 0
f'(0) = 0 + 1 = 1
equation of tangent : y = x
at (0,0) the function is increasing
so the point is (0,0)
f'(x) = x(-e^-x) + e^-x
when x = 0
f'(0) = 0 + 1 = 1
equation of tangent : y = x
at (0,0) the function is increasing
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.