Question

A particle P of mass m kg is attached to two fixed points A and B by two identical model springs, each of stiffness k and natural length lo. The point A is at a height 1/4lo above the point B. The particle is free to oscillate vertically under gravity. The stiffness of each spring is given by k = 4mg/lo. If m=2.64kg and lo=0.74m, calculate the natural frequency of the oscillation in rad s^-1, giving your answer to 3 decimal places. g=9.81 ms^-2
How do I find the answer?

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