Question

A particle of mass =6.50 kg moves with a velocity v1=x1i+y1j+z1k. A second particle of mass =3.50 kg moves with a velocity v2=x2i+y2j+z2k. And a third particle of mass =6.30 kg moves with a velocity v3=x3i+y3j+z3k. Here, (x1,y1,z1)=(-2.5,5.4,1.2), (x2,y2,z2)=(-2.3,0.1,-2.5) and (x3,y3,z3)=(3.3,-8.6,5.3).
What is the magnitude of the velocity of the center of mass for the system?

Answers

bobpursley
the sum of the masses.
then multiply each of the velocities by the fraction ofmass it contains, ie, on v1= 6.50/totalmass*(-2.5,5.4,1.2), or
v1=(-.997, 2.15, .479)

after scaling each of the three velocities with the mass fraction, then add the like components of each to get Vcm

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