Question
A particle of mass =6.50 kg moves with a velocity v1=x1i+y1j+z1k. A second particle of mass =3.50 kg moves with a velocity v2=x2i+y2j+z2k. And a third particle of mass =6.30 kg moves with a velocity v3=x3i+y3j+z3k. Here, (x1,y1,z1)=(-2.5,5.4,1.2), (x2,y2,z2)=(-2.3,0.1,-2.5) and (x3,y3,z3)=(3.3,-8.6,5.3).
What is the magnitude of the velocity of the center of mass for the system?
What is the magnitude of the velocity of the center of mass for the system?
Answers
bobpursley
the sum of the masses.
then multiply each of the velocities by the fraction ofmass it contains, ie, on v1= 6.50/totalmass*(-2.5,5.4,1.2), or
v1=(-.997, 2.15, .479)
after scaling each of the three velocities with the mass fraction, then add the like components of each to get Vcm
then multiply each of the velocities by the fraction ofmass it contains, ie, on v1= 6.50/totalmass*(-2.5,5.4,1.2), or
v1=(-.997, 2.15, .479)
after scaling each of the three velocities with the mass fraction, then add the like components of each to get Vcm
Related Questions
A particle of mass m1 = 2.5 kg moving along the x axis collides with a particle of mass m2 = 4.7 kg...
according to einstein's mass energy relation
M= m'/root[1-(v^2/c^2)]
Where M is mass...
A PARTICLE OF MASS M IS SHOT WITH an initial velocity v making an angle b with the horizontal,the pa...
A particle (mass = 4.0 g, charge = 50 mC) moves in a region of space where the electric field is uni...