Question

A particle A of mass 2.11 kg collides with another particle B of mass 3.86 kg. Their initial velocities are u1 = 2.16i + 0.88j and u2 = 0.7i + 1.12j just before impact. After collision, they both merged and becomes a composite particle, which travel with a velocity of V.

Calculate the speed |V|, a scalar, in ms-1. Give your answer to 3 decimal places.
the momentum of the center of mass stays constant.

p1 = m1*u1 = 4.5576i + 1.8568j
p2 = m2*u2 = 2.7020i + 4.3232j
p = p1+p2 = 7.2596i + 6.1800j
|p| = 9.5338
|v| = |p|/(m1+m2) = 1.597 m/s

Related Questions

Particle A has twice the mass of particle B, and carries three times the charge of B charge. Both pa... A particle of mass m0 is given a kinetic energy equal to one-third its rest-mass energy. How fast mu... 3. A particle of mass 0.5 kg has velocity 2 m/s. It is moving at constant velocity along a line th... A particle of mass 0.350 kg is attached to the 100-cm mark of a meter stick of mass 0.175 kg. The me... A particle with a mass of 6.64x10^-27 kg and a charge of +3.2x10^-19 C is accelerated from rest thro... A particle of mass m = 27 g slides inside a bowl whose cross section has circular arcs at each side... A particle of mass m1 is kept at x = 0 and another of mass m2 at x = d. When a third particle is kep... Particle A has very little mass in comparison to Particle B. Both particles are in the same atom. Wh... If a particle has a mass of 1 atomic mass unit and a charge of +1, what particle must it be? * Capti...