Asked by Aviance
A particle with a mass of m 1 equals 2.2 kg collides elastically with a particle of mass into equal 4.1 kg, as shown. After the Collision in one moves off at an angle sign one equals 30 degrees with a speed of 24 miles per second while M2 moves off at an angle send to equals -45 degrees with an unknown speed
Answers
Answered by
oobleck
conserve momentum
2.2v = 2.2v1 + 4.1v2
where velocities are vectors. Separate into x- and y-components.
2.2v = 2.2v1 + 4.1v2
where velocities are vectors. Separate into x- and y-components.
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