Asked by Joshua
A brick is thrown off a building at a 25 degree angle at 10m/s, it lands 40 meters away, How high is the building?
Answers
Answered by
drwls
Time of flight = t = (40 m)/(Vo*cos25)
= 4.41 s
since the horizontal velocity component is constant.
Vo*sin25*t - (1/2)gt^2 = -(Height)
since the vertical location is
-(Height) when it hits the ground
Height = 4.9 t^2 - 4.226 t
= 95.3 - 18.6 = 76.7 m
= 4.41 s
since the horizontal velocity component is constant.
Vo*sin25*t - (1/2)gt^2 = -(Height)
since the vertical location is
-(Height) when it hits the ground
Height = 4.9 t^2 - 4.226 t
= 95.3 - 18.6 = 76.7 m
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.