Asked by lisa

A brick is thrown upward from the top of a building at an angle of 35° to the horizontal and with an initial speed of 15 m/s. If the brick is in flight for 2.7 s, how tall is the building? (in m)
could someone help me please!!!
Answered by Damon
We just need to do the vertical part of the problem. I assume it hit the ground where H = 0

Vi = 15 sin 35 = 8.6 m/s up

H = Hi + Vi t - 4.9 t^2

0 = Hi + 8.6 (2.7) - 4.9 (2.7)^2

Hi = 12.5 meters
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