A brick is thrown vertically upward with an initial speed of 4.40 m/s from the roof of a building. If the building is 74.0 m tall, how much time passes before the brick lands on the ground?

Answer 1

Solve this equation for t:

-74 = 4.4 t - (g/2) t^2

g = 9.8 m/s^2

Take the root that is positive.