Asked by Alysse
A brick is thrown vertically upward with an initial speed of 4.40 m/s from the roof of a building. If the building is 74.0 m tall, how much time passes before the brick lands on the ground?
Answers
Answered by
drwls
Solve this equation for t:
-74 = 4.4 t - (g/2) t^2
g = 9.8 m/s^2
Take the root that is positive.
-74 = 4.4 t - (g/2) t^2
g = 9.8 m/s^2
Take the root that is positive.
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