Question
A stone is thrown vertically upward with the velocity of 49.0 m/s. (a) how high will it travel before it starts to fall? (b) how many seconds will it take the stone to reach the highest point?
Answers
Anonymous
v = Vi - 9.81 t
at top v = 0
0 = 49 - 9.81 t
t = 49/9.81
h = 49 t - 4.9 t^2
at top v = 0
0 = 49 - 9.81 t
t = 49/9.81
h = 49 t - 4.9 t^2