Question
An airplane is flying with a heading of 60 degrees east of north at 450 mph. A wind is blowing at 37 mph from the north. Find the plane's ground speed to the nearest mph and direction to the nearest degree.
Thanks.
Thanks.
Answers
the plane is traveling South with the wind at 37 miles per hour
It is flying North in the air at 450 cos 60 = 225
so its speed North = 225 - 37 = 188
its speed East is 450 sin 60 = 389
so
total speed = sqrt(188^2 + 389^2)
=sqrt (186665)
= 432 mph
tan angle east of north = 389/188 = 2.07
angle = 64.2 = 64 degrees
It is flying North in the air at 450 cos 60 = 225
so its speed North = 225 - 37 = 188
its speed East is 450 sin 60 = 389
so
total speed = sqrt(188^2 + 389^2)
=sqrt (186665)
= 432 mph
tan angle east of north = 389/188 = 2.07
angle = 64.2 = 64 degrees
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