Asked by Debbie
An airplane is flying at an altitude of 918 ft when it spots a person Due West at an angle of depression of 32 degrees and another due west at an angle of depression of 58 degrees. How far apart are the 2 people?
Answers
Answered by
Henry
Tan 32 = h/(X1+X2), (X1+X2) = h/Tan 32 =
918/Tan32 = 1469 Ft.
Tan 58 = h/X1, X1 = h/Tan 58 = 918/Tan58
= 574 Ft.
X1 + X2 = 1469.
574 + X2 = 1469.
X2 = Distance between the 2 people.
918/Tan32 = 1469 Ft.
Tan 58 = h/X1, X1 = h/Tan 58 = 918/Tan58
= 574 Ft.
X1 + X2 = 1469.
574 + X2 = 1469.
X2 = Distance between the 2 people.
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