Asked by Joe
An airplane is flying with an airspeed of 660 Kilometers per hour. The wind is blowing from 345 degrees at 35 km/h. What direction should the airplane take so that, with the wind, the plane will be flying in a direction of 72 degrees?
I can compute airspeed and actual direction using law of sines and cosines but not sure how to figure out the requested 72 degree part.
I can compute airspeed and actual direction using law of sines and cosines but not sure how to figure out the requested 72 degree part.
Answers
Answered by
Henry
X = hor. = 660 + 35cos345 = km/h.
Y = ver. = 35sin345 =
tanA = Y/X = -9.06 / 693.8 = -.0131,
A = -0.75 deg.
A + B = 72,
-0.75 + B = 72,
B = 72 + 0.75 = 72.75 deg. = Direction.
Y = ver. = 35sin345 =
tanA = Y/X = -9.06 / 693.8 = -.0131,
A = -0.75 deg.
A + B = 72,
-0.75 + B = 72,
B = 72 + 0.75 = 72.75 deg. = Direction.
Answered by
Henry
Vpw = Vp + Vw = 660[72o].
Vp + 35[345o] = 660[72].
Vp+35*Cos345+35*sin345=660*Cos72+660*sin72.
Vp + 33.8-9.1i = 204+627.7i.
Vp=204 + 627.7i -33.8+9.1i=170.2+636.8i
= 659km/h[75o].
Vp + 35[345o] = 660[72].
Vp+35*Cos345+35*sin345=660*Cos72+660*sin72.
Vp + 33.8-9.1i = 204+627.7i.
Vp=204 + 627.7i -33.8+9.1i=170.2+636.8i
= 659km/h[75o].
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.