Asked by Mike

What is the specific heat in J/g Celsius for a metal sample with a mass 95.6 g which absorbs 841 J of energy when it's temperature increases from 30.0 degrees Celsius to 98.0 degrees Celsius?
Answered by DrBob222
q = mc*delta T
Answered by Akou
841J=95.6g×c×68c =0.129/gc
There are no AI answers yet. The ability to request AI answers is coming soon!