Question
The specific heat of ice is 0.5 calories/gram.
60 grams of ice will require _____ calories to raise the temperature 1°C.
so i just do 0.5/60 ??
60 grams of ice will require _____ calories to raise the temperature 1°C.
so i just do 0.5/60 ??
Answers
You use those numbers but not that way.
mass ice x specific heat ice x (Tfinal-Tinitial).
60 g x 0.5 cal/g x (1) = ??
mass ice x specific heat ice x (Tfinal-Tinitial).
60 g x 0.5 cal/g x (1) = ??
and I got 30.
correct?
correct?
i got 30
right.
thank you
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