Asked by jenn

What is the specific heat of a metal if 24.8 g absorbs 65.7 cal of energy and the temperature rises from 20.2 degrees celsius to 24.5 degrees celsius?
Answered by DrBob222
q = mass x specific heat x (Tfinal-Tinitial)
65.7 = 24.8 x sp.h. x (24.5-20.3)
Solve for sp.h.
Answered by Sarah
11.4
Answered by Tiffany
q = mass x specific heat x (Tfinal-Tinitial) 65.7 = 24.8 x s.h. x (24.5-20.2)
0.616
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