Asked by Samuel

A man jumps from a great height and falls freely to the Earth. Another man jumps from the same height 1 s later. How much are the two men separated by, 2 s after the second man jumps?

I'm not sure exactly how to tackle this question. I'm sure I'm making it more complicated than it is supposed to be.

Thanks.
Answered by Dr. Jane
The second man is travelling for 2 seconds.

The first man is travelling for 3 seconds.

acceleration due to gravity = 9.8m/sec^2

d = vt
v = at
we can combine to get

d =at^2 a in this case is g.

You can find the distance of each jumper and find the difference.
Answered by Samuel
Great. Thanks a lot.
Answered by Dr. Jane
You are welcome.
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