Asked by Himanshu
A parachutist jumps from height 100m. He wants to reach at ground with zero velocity. For this purpose he switches on a parachute propeller after falling freely for certain height. Given that the parachute propeller is switched on total acceleration of the man varies with velocity as a = -2v, where v is instantaneous velocity of the man. Find the time after falling freely man should switch on parachute propeller for this purpose.
Answers
Answered by
Steve
since dv/dt = -2v
v(t) will be an exponential function, so it will never be zero. You sure you don't want to specify some small acceptable speed at touchdown?
Anyway, consider that after falling for k seconds,
v = -9.8k
and after t more seconds when s=0, you want v close to zero
v = -9.8k e^(-2t)
s = 100 - 9.8kt + 1/2 at^2
= 100 - 9.8kt - 9.8k*e^(-2t)*t^2
See what you can do with that.
v(t) will be an exponential function, so it will never be zero. You sure you don't want to specify some small acceptable speed at touchdown?
Anyway, consider that after falling for k seconds,
v = -9.8k
and after t more seconds when s=0, you want v close to zero
v = -9.8k e^(-2t)
s = 100 - 9.8kt + 1/2 at^2
= 100 - 9.8kt - 9.8k*e^(-2t)*t^2
See what you can do with that.
Answered by
Suraj kumar verma
Can't you make it little easier ? We asked this question so that we can solve this difficult question but this solution is more difficult than the question itself.
Answered by
Anonymous
Retry
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