Asked by Sammeh
A diver jumps from a height of 24.0m into a swimming pool. What's her speed when she enters the water? (21.7m/s)
if the diver stops after sinking 3m into the water, what's the acceleration in the water? (78.4m/s^2)
if the diver stops after sinking 3m into the water, what's the acceleration in the water? (78.4m/s^2)
Answers
Answered by
bobpursley
vf^2=2gh=2*9.8*24
v=21.6m/s
in the water
vf^2=Vi^2+2ad
a= 21.7^2/6
v=21.6m/s
in the water
vf^2=Vi^2+2ad
a= 21.7^2/6
Answered by
Sammeh
thanks so much!
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