Asked by jelloh

a diver jumps from a platform at time t=0 seconds. the distance of the diver above water level at time t is given by s(t)=-4.9t^2 +4.9t+10, where s is in meters

c.) find when velocity equal zero. find the maximum height of the diver



thank you
Answered by Steve
v(t) = -9.8t + 4.9
so, when is v=0?
Use that value of t to find s(t)
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