Asked by jelloh
a diver jumps from a platform at time t=0 seconds. the distance of the diver above water level at time t is given by s(t)=-4.9t^2 +4.9t+10, where s is in meters
c.) find when velocity equal zero. find the maximum height of the diver
thank you
c.) find when velocity equal zero. find the maximum height of the diver
thank you
Answers
Answered by
Steve
v(t) = -9.8t + 4.9
so, when is v=0?
Use that value of t to find s(t)
so, when is v=0?
Use that value of t to find s(t)
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