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Asked by Brian

The two plates of a capacitor hold +3200 µC and -3200 µC of charge, respectively, when the potential difference is 700 V. What is the capacitance?
12 years ago

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Answered by Ryan
Cap=charge/potential 3200/700=4.57
8 years ago
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The two plates of a capacitor hold +3200 µC and -3200 µC of charge, respectively, when the potential difference is 700 V. What is the capacitance?

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