Asked by lee
The voltage across the plates of a capacitor at any time t seconds is given by V=Ve -t/CR, where V,C and r are constants. Given V = 300 Volts, C =0.12*10-6 F and R = 4*10 6 ohms
Find the initial rate of change of voltage
and the rate of change of voltage after 0.5 seconds
Find the initial rate of change of voltage
and the rate of change of voltage after 0.5 seconds
Answers
Answered by
Damon
I think you probably mean
V = Vo e^(-t/RC)
where Vo is 300 volts and the chrge is discharged through the resistor
here 1/RC = 1/(.12*4) = 2.08
so
V = 300 e^-2.08 t
dV/dt = -2.08(300) e^-2.08 t
= -625 e^-2.08 t volts/second
obviously when t = 0 this is -625
you can put in .5 or anything else for t
V = Vo e^(-t/RC)
where Vo is 300 volts and the chrge is discharged through the resistor
here 1/RC = 1/(.12*4) = 2.08
so
V = 300 e^-2.08 t
dV/dt = -2.08(300) e^-2.08 t
= -625 e^-2.08 t volts/second
obviously when t = 0 this is -625
you can put in .5 or anything else for t
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