Question

the foci of an ellipse are (0,2) (0,-2) and the eccentricity is 1/2. determine the equation of the ellipse. write your answer in standard form.
e = c/a = 1/2, so a = 2c
a^2 = c^2+b^2
4c^2 = c^2+b^2
3c^2 = b^2
c = 2, so b^2 = 12, and a^2 = 16

x^2/16 + y^2/12 = 1

Related Questions

Given that the ellipse x^2/a^2 + y^2/b^2 =1 has foci at(+/-ae,0)where e is the eccentricity and b^2=... Hi! Can someone check my answers? Thanks! Questions: 1.) What are all of the foci's for t... Find the equation of an ellipse that have eccentricity 2/5 and foci (-1, 3) and (3, 3) . If the eccentricity of an ellipse is 0.571 and distance between the foci of that ellipse is 3,410,00...