Asked by Ciara
Locate the foci of the ellipse. Show your work.
𝑥2/36+ y2/11=1
𝑥2/36+ y2/11=1
Answers
Answered by
Steve
If you mean
x^2/36 + y^2/11 = 1
then you can see that since 36 > 11, the major axis is on the x-axis.
So, since b^2+c^2 = a^2, c^2=25, and the foci are at (±5,0)
x^2/36 + y^2/11 = 1
then you can see that since 36 > 11, the major axis is on the x-axis.
So, since b^2+c^2 = a^2, c^2=25, and the foci are at (±5,0)
Answered by
Reiny
I will assume your ellipse is
x^2/36 + y^2/11 = 1
so a = 6 and b = √11 with the foci along the x-axis
for that kind of ellipse,
c^2 = a^2 - b^2
= 36 - 11 = 25
c = ± 5
thus the foci are (5,0) and (-5,0)
x^2/36 + y^2/11 = 1
so a = 6 and b = √11 with the foci along the x-axis
for that kind of ellipse,
c^2 = a^2 - b^2
= 36 - 11 = 25
c = ± 5
thus the foci are (5,0) and (-5,0)
Answered by
Ciara
Thank you guys :)
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